Section Modulus Circle
输入圆截面直径 d,求抗弯截面模量。
| Item | Formula / Note | Source / Standard |
|---|---|---|
| Section modulus | W = I / c = pi · d^3 / 32, where c is the distance from the neutral axis to the extreme fibre | Roark RJ, Young WC, Formulas for Stress and Strain, McGraw-Hill |
| Relation to bending stress | sigma_max = M / W, where M is the bending moment | Timoshenko SP, Gere JM, Mechanics of Materials |
| Hollow circular section | W = pi · ( D^4 - d^4 ) / ( 32 · D ) | Roark RJ, Young WC, Formulas for Stress and Strain |
| Units | The unit is length cubed, e.g. mm^3 | ISO 80000-4:2019, Quantities and units - Part 4: Mechanics |
工作与生活中的相关计算与查询。
圆截面抗弯截面模量 Z=π·d³/32(d 直径):纯弯曲下截面抵抗弯矩的能力,Z 越大越不易弯断。
弯曲正应力 σ=M/Z(M 弯矩)。用于轴、柱等圆截面构件强度校核;实心圆 Z 大于同面积空心圆吗?同外径下实心更大,但空心更轻。