最坏情况累积

T_total = ΣT_i

Sum the absolute tolerances of all components in a linear dimension chain to conservatively assess assembly clearance or interference.

📐 计算公式
公差累积(本页代码口径,公差序列按逗号分隔输入):最坏情况总公差=Σ|公差项|(mm);联动量:平均单环=总公差÷环数、统计平方根 RSS 总公差=√(Σ公差项²)、极端法与统计法之差=Σ|t|−RSS。校验:无强校验(split+Number 解析,非法项以 NaN 带入求和)。判据:无固定分级,环数越多 RSS 相对最坏法节省越显著,RSS 恒不大于最坏总公差。

线性尺寸链最坏累积 = 各环公差绝对值之和。

Formula & Standard References

Item Formula / Note Source / Standard
Worst-case stack-up T_total = sum T_i, assuming every contributor sits at its limit simultaneously ISO 8015:2011, Geometrical product specifications (GPS) - Fundamentals - Concepts, principles and rules
Statistical stack-up For independent contributors, T_total = sqrt( sum T_i^2 ) NIST/SEMATECH e-Handbook of Statistical Methods (variances of independent terms add)
Cost of the worst case Guarantees full interchangeability at the price of the tightest component tolerances ISO 8015:2011, Geometrical product specifications (GPS) - Fundamentals
Trade-off of the statistical method Accepts a small fraction of out-of-tolerance assemblies in exchange for wider tolerances NIST/SEMATECH e-Handbook of Statistical Methods (statistical tolerancing)
📌 计算说明
  • 最坏情况偏保守。
  • 统计法可用 RSS 替代。

📚 深度解析:最坏情况公差叠加

💡 常见使用场景

公式
总公差 = sum(|t_i|)(线性叠加)。例:三件公差 ±0.05、±0.03、±0.02,总 ±0.10 mm。
尺寸链公差 0.12,−0.05,0.08,0.03
最坏累积=0.12+0.05+0.08+0.03=0.280 mm,平均单环 0.070 mm。负公差取绝对值计入,结果是最保守的估计。

❓ 常见问题(FAQ)

与 RSS?
最坏叠加保守,RSS(平方和根)统计更紧,按风险选。
用场?
关键配合、安全件取最坏情况。