可区分类别数(NDC)计算器

Number of Distinct Categories (NDC)

Compute NDC = 1.41 × PV/GRR from part-to-part variation and measurement system error; NDC ≥ 5 is considered effective.

📐 计算公式
测量系统 NDC(本页代码口径):NDC=1.41×零件变差 PV÷测量系统变差 GRR(可区分类别数,保留 2 位);联动量:GRR 占过程变差比=GRR÷PV×100(%,分母按 10⁻¹² 兜底)、PV÷GRR 比、NDC 取整(向下取整)。校验:两项空值即提示并中止。判据:页面无阈值分支;通行判读口径 NDC≥5 测量系统方可接受,不足需降低测量变异。

输入零件间变差 PV 与测量系统误差 GRR,求 NDC。

Formula & Standard References

Item Formula / Note Source / Standard
Number of distinct categories ndc = 1.41 · PV / GRR, truncated to an integer AIAG, Measurement Systems Analysis (MSA) Reference Manual, 4th ed. (2010)
Criterion ndc ≥ 5 indicates the system can distinguish differences between parts AIAG, Measurement Systems Analysis (MSA) Reference Manual, 4th ed. (2010)
Relation to %GRR ndc complements %GRR in assessing measurement system discrimination AIAG, Measurement Systems Analysis (MSA) Reference Manual, 4th ed. (2010)
Part variation PV is the true variation between parts and forms the numerator of ndc AIAG, Measurement Systems Analysis (MSA) Reference Manual, 4th ed. (2010)
📌 计算说明
  • NDC≥5 测量系统可区分零件。
  • 1.41×5 → 7.05。

📚 深度解析:可区分类别数 (NDC)

💡 常见使用场景

公式
NDC = 1.41*(PV/GRR)。例:过程变异 PV=0.02、GRR=0.0028,NDC=1.41*7.14≈10。
零件间变差 PV=6.5,GRR=0.8
NDC=1.41×6.5/0.8=11.46,远大于 5,说明该测量系统足以分辨出零件之间的真实差异。

❓ 常见问题(FAQ)

判据?
NDC≥5 量具足够分辨过程变异。
不足?
需提高分辨率或换量具。