Compute regular polygon area from side count n (n ≥ 3) and side length s using A = n·s²/(4·tan(π/n)).
由边数与边长求正多边形面积(n≥3)。
| Item | Formula / Note | Source / Standard |
|---|---|---|
| Regular polygon area | A = ½·n·s·a (perimeter × apothem/2) | Polygon geometry |
| Apothem | a = s/(2 tan(π/n)) | Regular polygon |
| Circumradius form | A = (n/2)R² sin(2π/n) | Trigonometric form |
| Circle limit | Tends to πR² as n→∞ | Limit concept |
| Validity | Only regular polygons | Geometric constraint |
| Units | Squared length units | Dimensional rules |